What is the maximum number of 2/0 AWG THW aluminum compact conductors permitted in a 2 1/2-inch PVC conduit, Schedule 80?

To determine the maximum number of 2/0 AWG THW aluminum compact conductors permitted in a 2 1/2-inch PVC conduit, we refer to the conduit fill calculations as prescribed in the National Electrical Code (NEC). The NEC outlines guidelines for how many conductors can be run through conduits to ensure safety and prevent overheating.

First, we find the internal area of a 2 1/2-inch PVC conduit. The diameter of this conduit translates into a specific cross-sectional area. For example, a 2 1/2-inch conduit has an approximate internal diameter of 2.5 inches and a calculated area of about 4.91 square inches.

Next, the area of a single 2/0 AWG aluminum conductor needs to be calculated. The NEC provides standardized values for conductor areas, and for a 2/0 AWG aluminum conductor, the area is around 0.067 square inches.

To find the maximum number of conductors, you need to divide the total conduit area by the cross-sectional area of one conductor. When you perform the calculation using the internal conduit area divided by the area of a 2/0 conductor, you ultimately find:

4.91 square inches